Question

giải pt:

x + \(\dfrac{3}{x}\) = 1

Answer 1

\(x=1-3/x=>x=x/x-3/x=>x=x-3/x=>2x=x-3=>2x-x=-3=>x=-3\)

Answer 2

\(x+\dfrac{3}{x}=\dfrac{x^2+3}{x}=1\Rightarrow x=x^2+3\Rightarrow x-x^2=3\Rightarrow x\left(1-x\right)=3\)

Đến đây bạn giải tìm nghiệm.

Answer 3

ĐKXĐ:\(x\ne0\)

\(x+\dfrac{3}{x}=1\\ \Leftrightarrow\dfrac{x^2}{x}+\dfrac{3}{x}-\dfrac{x}{x}=0\\ \Leftrightarrow\dfrac{x^2-x+3}{x}=0\\ \Rightarrow x^2-x+3=0\\ \Leftrightarrow\left(x^2-x+\dfrac{1}{4}\right)+\dfrac{11}{4}=0\\ \Leftrightarrow\left(x-\dfrac{1}{2}\right)^2+\dfrac{11}{4}=0\left(vô.lí\right)\)