`2(x + 3)+4(2 - 2x) = 2(x-2)`
`=> 2x + 6 + 8 - 8x = 2x - 4`
`=> -6x + 14 = 2x - 4`
`=> -6x - 2x = -4 - 14`
`=> -4x = -18`
`=> x = 9/4`
Vậy: `S={9/4}`
\(2\left(x+3\right)+4\left(2-2x\right)=2\left(x-2\right)\)
=>\(2x+6+8-8x=2x-4\)
=>\(-6x+14=2x-4\)
=>-8x=-18
=>\(x=\dfrac{18}{8}=\dfrac{9}{4}\)
2(x+3) + 4(2-2x) = 2(x-2)
2x + 6 +8 - *x = 2x-4
-6x + 14 = 2x -4
-6x -2x = -4 -14
-8x = -18
x = 18/8 = 9/4