Ta có: \(\frac58\left(x-2\right)\left(\frac{90}{x}+1\right)+\frac38\left(x-2\right)\cdot\frac{90}{x}=90\)
=>\(\frac58\cdot\left(90+x-\frac{180}{x}-2\right)+\frac{270}{8x}\left(x-2\right)=90\)
=>\(\frac{450}{8}+\frac58x-\frac{900}{8x}-\frac54+\frac{270}{8}-\frac{540}{8x}=90\)
=>\(\frac{720}{8}+\frac58x-\frac{1440}{8x}-\frac54-90=0\)
=>\(\frac58x-\frac{180}{x}-\frac54=0\)
=>\(\frac{5x-10}{8}-\frac{180}{x}=0\)
=>\(\frac{x\left(5x-10\right)-180\cdot8}{8x}=0\)
=>x(5x-10)-1440=0
=>5x(x-2)-1440=0
=>x(x-2)-288=0
=>\(x^2-2x-288=0\)
=>(x-18)(x+16)=0
=>x=18(nhận) hoặc x=-16(loại)
Khi x=18 thì y=90/18=5(nhận)


giải hộ mình mấy bài này vs ạ !



