Question

Ai giải hộ e vs ạ

Answer 1

Câu 3: 

a: Ta có: \(\left(1-4x\right)\left(x-1\right)+\left(2x+1\right)\left(2x+3\right)=38\)

\(\Leftrightarrow x-1-4x^2+4x+4x^2+6x+2x+3=38\)

\(\Leftrightarrow13x=36\)

hay \(x=\dfrac{36}{13}\)

b: Ta có: \(\left(2x+3\right)\left(x+2\right)-\left(x-4\right)\left(2x-1\right)=75\)

\(\Leftrightarrow2x^2+4x+3x+6-2x^2+x+8x-4=75\)

\(\Leftrightarrow15x=73\)

hay \(x=\dfrac{73}{15}\)