a.
\(\Leftrightarrow\dfrac{1}{2}sinx-\dfrac{\sqrt{3}}{2}cosx=0\)
\(\Leftrightarrow sin\left(x-\dfrac{\pi}{3}\right)=0\)
\(\Leftrightarrow x-\dfrac{\pi}{3}=k\pi\)
\(\Leftrightarrow x=\dfrac{\pi}{3}+k\pi\)
b.
\(\Leftrightarrow\sqrt{2}sin\left(x+\dfrac{\pi}{4}\right)=0\)
\(\Leftrightarrow sin\left(x+\dfrac{\pi}{4}\right)=0\)
\(\Leftrightarrow x+\dfrac{\pi}{4}=k\pi\)
\(\Leftrightarrow x=-\dfrac{\pi}{4}+k\pi\)
a: \(sinx-\sqrt{3}\cdot cosx=0\)
=>\(\sqrt{3}\cdot cosx=sinx\)
=>\(\dfrac{sinx}{cosx}=\sqrt{3}\)
=>\(tanx=\sqrt{3}\)
=>\(x=\dfrac{\Omega}{3}+k\Omega\)
b: \(sinx+cosx=0\)
=>\(\sqrt{2}\cdot cos\left(x-\dfrac{\Omega}{4}\right)=0\)
=>\(cos\left(x-\dfrac{\Omega}{4}\right)=0\)
=>\(x-\dfrac{\Omega}{4}=\dfrac{\Omega}{2}+k\Omega\)
=>\(x=\dfrac{3}{4}\Omega+k\Omega\)
