`1)\sqrt{9x^2-12x+4}=\sqrt{x^2}`
`<=>\sqrt{(3x-2)^2}=\sqrt{x^2}`
`<=>|3x-2|=|x|`
`<=>[(3x-2=x),(3x-2=-x):}`
`<=>[(x=1),(x=1/2):}`
Vậy `S={1;1/2}`
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`2)\sqrt{x^2-4x+4}=\sqrt{4x^2-12x+9}`
`<=>\sqrt{(x-2)^2}=\sqrt{(2x-3)^2}`
`<=>|x-2|=|2x-3|`
`<=>[(x-2=2x-3),(x-2=3-2x):}`
`<=>[(x=1),(x=5/3):}`
Vậy `S={1;5/3}`