Giải bài này hộ mình với!!!
Bài 1 :
a) \(sin4x=sin\dfrac{\pi}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}4x=\dfrac{\pi}{5}+k2\pi\\4x=\pi-\dfrac{\pi}{5}+k2\pi\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{20}+k\dfrac{\pi}{2}\\x=\dfrac{\pi}{5}+k\dfrac{\pi}{2}\end{matrix}\right.\)
e) \(2sin\dfrac{x}{2}+\sqrt[]{3}=0\)
\(\Leftrightarrow sin\dfrac{x}{2}=-\dfrac{\sqrt[]{3}}{2}\)
\(\Leftrightarrow sin\dfrac{x}{2}=sin\left(-\dfrac{\pi}{3}\right)\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{x}{2}=-\dfrac{\pi}{3}+k2\pi\\\dfrac{x}{2}=\pi+\dfrac{\pi}{3}+k2\pi\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2\pi}{3}+k2\pi\\x=\dfrac{8\pi}{3}+k2\pi\end{matrix}\right.\)
m) \(\sqrt[]{3}tan2x-3=0\)
\(\Leftrightarrow tan2x=\sqrt[]{3}\)
\(\Leftrightarrow tan2x=tan\dfrac{\pi}{3}\)
\(\Leftrightarrow2x=\dfrac{\pi}{3}+k\pi\)
\(\Leftrightarrow x=\dfrac{\pi}{6}+\dfrac{k\pi}{2}\)
