Dd mới có pH = 7 ⇒ Pư vừa đủ
Có: \(n_{Ba\left(OH\right)_2}=0,05\left(mol\right)\)
PT: \(Ba\left(OH\right)_2+H_2SO_4\rightarrow BaSO_4+2H_2O\)
______0,05_____0,05______0,05 (mol)
\(\Rightarrow V_{ddH_2SO_4}=\dfrac{0,05}{0,1}=0,5\left(l\right)\)
\(m_{BaSO_4}=0,05.233=11,65\left(g\right)\)