= \(\dfrac{6x}{x-2}+\dfrac{-12}{x-2}\) = \(\dfrac{6x-12}{x-2}=\dfrac{6\left(x-2\right)}{x-2}=6\)
Rút gọn:
A = \(\dfrac{x+3}{x^2-6x+9}:\left(\dfrac{12-x^2}{x^2-3x}-\dfrac{1}{3-x}+\dfrac{x+3}{x}\right)\)
\(\dfrac{2}{x^2-5x+6}-\dfrac{2}{x^2-9}\)
help me
Giai bptr sau
\(\dfrac{6x+5}{4}-\dfrac{x-3}{2}< \dfrac{6x-1}{3}+\dfrac{7x-1}{12}\)
Giải phương trình\(\dfrac{1}{x+2}+\dfrac{6x+12}{x^3+8}-\dfrac{7}{x^2-2x+4}=0\)
\(\dfrac{x^2+2x}{2x+12}+\dfrac{x-6}{x}+\dfrac{108-6x}{2x\left(x+6\right)}\)
câu 1: (x-2)(x2+2x+4)+25x=x(x+5)(x-5)+8
câu 2: \(\dfrac{x+5}{4}\)+\(\dfrac{3+2x}{3}\)=\(\dfrac{6x-1}{3}\)-\(\dfrac{1-2x}{12}\)
câu 3:\(\dfrac{x-4}{3}\)-\(\dfrac{3x-1}{12}\)=\(\dfrac{3x+1}{4}\)+\(\dfrac{9x-2}{8}\)
Giúp mình với ai làm mà có lời giải rõ á là mình tym nha làm ơn 
Giải các phương trình sau:
\(e.\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
\(f.\dfrac{6x+1}{x^2-7x+10}+\dfrac{5}{x-2}=\dfrac{3}{x-5}\)
\(g.\dfrac{2}{x+2}-\dfrac{2x^2+16}{x^3+8}=\dfrac{5}{x^2-2x+4}\)
\(h.\dfrac{8}{x-8}+\dfrac{11}{x-11}=\dfrac{9}{x-9}+\dfrac{10}{x-10}\)
Giải các phương trình sau:
a) 2,3 - 2(0,7 + 2) = 3,6 - 1,7x
b) \(\dfrac{5x+7}{4}-\dfrac{3x+5}{8}=\dfrac{4x+9}{5}-\dfrac{x-9}{3}\)
c) \(\dfrac{2x-1}{4}+\dfrac{x-3}{3}=\dfrac{4x-2}{3}-\dfrac{6x+7}{12}\)
d) (x - 1)(x + 2) - x(x + 3) = 8
Tìm GTNN:
a) \(\dfrac{1}{-x^2+2x-4}\)
b) \(\dfrac{12}{12x-4x^2-13}\)
c) \(\dfrac{x^2-4x-4}{x^2-4x+5}\)
d) \(\dfrac{15}{-6x^2-5y^2+10xy-4x+10y-19}\)
e)\(\dfrac{x^2-2011}{4.\left(x^2+1\right)}\)
