Question

\(\dfrac{17}{11}\)+\(\left(\dfrac{6}{5}-\dfrac{16}{11}\right)\)+\(\dfrac{26}{5}\)=\(\dfrac{17}{11}\)

giúp mình câu này ạ

Answer 1

Sửa đề: \(\dfrac{17}{11}+\left(\dfrac{6}{5}-\dfrac{16}{11}\right)+\dfrac{26}{5}+\dfrac{17}{11}\)

\(=\dfrac{17}{11}+\dfrac{6}{5}-\dfrac{16}{11}+\dfrac{26}{5}+\dfrac{17}{11}\)

\(=\dfrac{18}{11}+\dfrac{32}{5}=\dfrac{18\cdot5+32\cdot11}{55}=\dfrac{442}{55}\)

 

Answer 2

Sửa đề: \(\dfrac{17}{11}\) + \((\dfrac{6}{5}\) \(-\) \(\dfrac{16}{11}\) \()\) + \(\dfrac{26}{5}\) + \(\dfrac{17}{11}\)

= \(\dfrac{17}{11}\)+ \(\dfrac{6}{5}\) \(-\) \(\dfrac{16}{11}\) + \(\dfrac{26}{5}\) + \(\dfrac{17}{11}\)

= (\(\dfrac{17}{11}\)+ \(\dfrac{17}{11}\)+\(\dfrac{16}{11}\)) + (\(\dfrac{6}{5}\)+ \(\dfrac{26}{5}\))

= \(\dfrac{18}{11}\)\(+\)\(\dfrac{32}{5}\)

=\(\dfrac{442}{55}\)