a: ĐKXĐ: x<>0; x<>1
\(P=\dfrac{x\left(x+1\right)}{\left(x-1\right)^2}:\dfrac{x^2-1+x+2-x^2}{x\left(x-1\right)}\)
\(=\dfrac{x\left(x+1\right)}{\left(x-1\right)^2}\cdot\dfrac{x\left(x-1\right)}{x+1}=\dfrac{x^2}{x-1}\)
b: |2x+1|=3
=>x=1(loại); x=-2(nhận)
Khi x=-2 thì P=4/-3=-4/3
c: P=-1/2
=>x^2/x-1=-1/2
=>2x^2=-x+1
=>2x^2+x-1=0
=>2x^2+2x-x-1=0
=>(x+1)(2x-1)=0
=>x=1/2; x=-1