a: ĐKXĐ: \(\left\{{}\begin{matrix}x\ge0\\x\ne1\end{matrix}\right.\)
b: Ta có: \(A=\dfrac{3x+2\sqrt{x}-5}{x+\sqrt{x}-2}+\dfrac{1}{\sqrt{x}+2}-\dfrac{1}{1-\sqrt{x}}\)
\(=\dfrac{3x+2\sqrt{x}-5+\sqrt{x}-1+\sqrt{x}+2}{\left(\sqrt{x}+2\right)\cdot\left(\sqrt{x}-1\right)}\)
\(=\dfrac{3x+4\sqrt{x}-4}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\)
\(=\dfrac{3\sqrt{x}-2}{\sqrt{x}-1}\)