Ta có: x-y-z=0 suy ra:
a = b + c (1)
b = a - c (2)
-c = b - a (3)
A=(1-c/a)(1-a/b)(1+b/a)
suy ra: A= (a-c/a)(b-a/b)(a+b/c)
Thay (1) (2) (3) ta có:
\(\dfrac{b}{a}-\left(\dfrac{c}{b}\right)\left(\dfrac{a}{c}\right)=\dfrac{\left(b.-c.a\right)}{\left(a.b.c\right)}\)
= \(-\dfrac{abc}{abc}\)