Question

A=2\(\sqrt{\dfrac{1}{2}}+\dfrac{2}{\sqrt{2}}-\sqrt{8}\)

Answer 1

\(A=\sqrt{2}+\sqrt{2}-2\sqrt{2}=0\)

Answer 2

`A=2\sqrt{1/2}+2/\sqrt{2}-\sqrt{8}`

`A=2. 1/\sqrt{2}+[(\sqrt{2})^2]/\sqrt{2}-\sqrt{2^2 .2}`

`A=\sqrt{2}+\sqrt{2}-2\sqrt{2}`

`A=0`

Answer 3

\(=2\dfrac{1}{\sqrt{2}}+\dfrac{2}{\sqrt{2}}-\sqrt{8}\\ =\dfrac{4}{\sqrt{2}}-\sqrt{4\cdot2}\\ =2\sqrt{2}-2\sqrt{2}\\ =0\)