7/5 + 8/5( x+1)= 3
8/5(x+1) = 3 - 7/5
8/5(x+1) = 8/5
x+1 = 8/5:8/5
x+1 = 1
=> x = 1-1 = 0
Vậy x = 0
\(\dfrac{7}{5}+\dfrac{8}{5}.\left(x+1\right)=3\\ \dfrac{8}{5}.\left(x+1\right)=3-\dfrac{7}{5}=\dfrac{8}{5}.\left(x+1\right)=\dfrac{8}{5}\\ x+1=\dfrac{8}{5}:\dfrac{8}{5}\\ x+1=1\\ \Rightarrow x=0\)