\(\sqrt{7+4\sqrt{3}}-\left(4\sqrt{3}-7\right)^2\\ =\sqrt{2^2+2.2.\sqrt{3}+\left(\sqrt{3}\right)^2}-\left|4\sqrt{3}-7\right|\\ =\sqrt{\left(2+\sqrt{3}\right)^2}-\left|4\sqrt{3}-7\right|\\ =\left|2+\sqrt{3}\right|-\left|4\sqrt{3}-7\right|\\ =2+\sqrt{3}-4\sqrt{3}-7\\ =-5-3\sqrt{3}\)
Trong các số sau, số nào là số nguyên:
a. x= căn 7+4 căn 3 + căn 7-4 căn 3
b. y= căn 7 +4 căn 3 - căn 7-4 căn 3
1+2+3+4+5+6+7+8+9-1-2-3-4-5-6-7-8-9*1*2*3*4*5*6*7*8*9:1:2:3:4:5:6:7:8:9=???
Tính
a) \(\sqrt{7-4\sqrt{3}}-\sqrt{7+4\sqrt{3}}\)
b) \(\sqrt{4+\sqrt{7}} -\sqrt{4-\sqrt{7}}\)
c) \(\sqrt{4-\sqrt{10-2\sqrt{5}}}-\sqrt{4+\sqrt{10-2\sqrt{5}}}\)
(7√3−3√7)÷(√7−√3)+4÷(5−√21)−6√7÷√3
a) √(4-√7)-√(4+√7) b)√(3+√5)+√(3-√5)
c)√(2+√3)-√(2-√3)
Tính GTBT:
\(B=\frac{4+\sqrt{7}}{3\sqrt{2}+\sqrt{4+\sqrt{7}}}+\frac{4-\sqrt{7}}{3\sqrt{2}-\sqrt{4-\sqrt{7}}}\)
\(\dfrac{4}{\sqrt{7}-\sqrt{3}}-\dfrac{4}{\sqrt{7}+\sqrt{3}}\)
THỰC HIỆN PHÉP TÍNH
1,\(\sqrt{3+\sqrt{5}}.\sqrt{2}\)
2,\(\sqrt{3-\sqrt{5}.\sqrt{8}}\)
3,\((\sqrt{\dfrac{3}{4}}-\sqrt{3}+5\sqrt{\dfrac{4}{3})}.\sqrt{12}\)
4,\((\sqrt{\dfrac{1}{7}}-\sqrt{\dfrac{16}{7}}+\sqrt{7}):\sqrt{7}\)
5, \(\sqrt{36-12\sqrt{5}}:\sqrt{6}\)
6,\(\sqrt{3-\sqrt{5}:}\sqrt{2}\)
tính
a, \(A=2\sqrt{12}-3\sqrt{48}+4\sqrt{75}\)
\(B=\sqrt{\frac{4-\sqrt{7}}{4+\sqrt{7}}}+\sqrt{\frac{4+\sqrt{7}}{4-\sqrt{7}}}\)
c, \(C=\frac{3-2\sqrt{3}}{\sqrt{3}}+\frac{6}{3+\sqrt{3}}\)
d,
