\(\dfrac{7\sqrt{3}-3\sqrt{7}}{\sqrt{7}-\sqrt{3}}+\dfrac{4}{5-\sqrt{21}}-\dfrac{6\sqrt{7}}{\sqrt{3}}=\dfrac{\sqrt{3}\sqrt{7}\left(\sqrt{7}-\sqrt{3}\right)}{\sqrt{7}-\sqrt{3}}+\dfrac{4\left(5+\sqrt{21}\right)}{4}-\dfrac{\sqrt{252}}{\sqrt{3}}=\sqrt{21}+5+\sqrt{21}-2\sqrt{21}=5\)