\(\dfrac{4}{\sqrt{7}-\sqrt{3}}-\dfrac{4}{\sqrt{7}+\sqrt{3}}\\ =\dfrac{4\left(\sqrt{7}+\sqrt{3}\right)}{\left(\sqrt{7}-\sqrt{3}\right)}-\dfrac{4\left(\sqrt{7}-\sqrt{3}\right)}{\left(\sqrt{7}+\sqrt{3}\right)}\\ =\dfrac{4\sqrt{7}+4\sqrt{3}-4\sqrt{7}+4\sqrt{3}}{\left(\sqrt{7}-\sqrt{3}\right)\left(\sqrt{7}+\sqrt{3}\right)}\\ =\dfrac{8\sqrt{3}}{7-3}\\ =\dfrac{8\sqrt{3}}{4}\\ =2\sqrt{3}\)