\(\left(2x-5\right)^2=\left(x-\dfrac{5}{2}\right)^2\\ \Leftrightarrow\left[{}\begin{matrix}2x-5=x-\dfrac{5}{2}\\2x-5=\dfrac{5}{2}-x\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\3x=\dfrac{15}{2}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=\dfrac{5}{2}\end{matrix}\right.\\ \Leftrightarrow x=\dfrac{5}{2}\)
Vậy x = \(\dfrac{5}{2}\)
\(\left(2x-5\right)^2=\left(x-\dfrac{5}{2}\right)^2\)
\(\Leftrightarrow2x-5=x-\dfrac{5}{2}\)
\(\Leftrightarrow2x-x=-\dfrac{5}{2}+5\)
\(\Leftrightarrow x=\dfrac{5}{2}\)
