Question

(√18 - √8 ) : √2

Answer 1

\(=\dfrac{3\sqrt{2}-2\sqrt{2}}{\sqrt{2}}=\dfrac{\sqrt{2}\left(3-2\right)}{\sqrt{2}}=3-2=1\)

Answer 2

\(\left(\sqrt{18}-\sqrt{8}\right):\sqrt{2}\)

\(=\left(\sqrt{18}-\sqrt{8}\right)\dfrac{1}{\sqrt{2}}\)

\(=\dfrac{\sqrt{18}}{\sqrt{2}}-\dfrac{\sqrt{8}}{\sqrt{2}}\)

\(=\dfrac{\sqrt{9}\sqrt{2}}{\sqrt{2}}-\dfrac{\sqrt{4}\sqrt{2}}{\sqrt{2}}\)

\(=\sqrt{9}-\sqrt{4}\)

\(=3-2=1\)

Answer 3

\(=\dfrac{3\sqrt{2}-2\sqrt{2}}{\sqrt{2}}=1\)

Answer 4

\(\left(\sqrt{18}-\sqrt{8}\right):\sqrt{2}=\left(3\sqrt{2}-2\sqrt{2}\right):\sqrt{2}=\sqrt{2}:\sqrt{2}=1\)