Question

(1/2x-3) ^3

Answer 1

\(\left(\dfrac{1}{2x-3}\right)^3=\dfrac{1}{8x^3-36x^2+18x-9}\)

Answer 2

\(\left(\dfrac{1}{2}x-3\right)^3=\dfrac{1}{8}x^3-\dfrac{9}{4}x^2+\dfrac{27}{2}x-27\)

Answer 3

\(=\dfrac{1}{8}x^3-\dfrac{9}{4}x^2+\dfrac{27}{2}x-27\)