Question

Answer 1

a: ĐKXĐ: x>0

\(A=\dfrac{x+\sqrt{x}+1}{\sqrt{x}\left(\sqrt{x}+1\right)}\cdot\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{\sqrt{x}}=\dfrac{x+\sqrt{x}+1}{\sqrt{x}}\)

b: ĐKXĐ: x>=0; x<>4

\(B=\dfrac{x+12+\sqrt{x}-2-4\sqrt{x}-8}{x-4}\)

\(=\dfrac{x-3\sqrt{x}+2}{x-4}=\dfrac{\sqrt{x}-1}{\sqrt{x}+2}\)

c: ĐKXĐ: \(x>=0;x< >1\)

\(C=\dfrac{\sqrt{x}+1+\sqrt{x}}{x-1}:\dfrac{\sqrt{x}-\sqrt{x}+1}{\sqrt{x}-1}\)

\(=\dfrac{2\sqrt{x}+1}{x-1}\cdot\dfrac{\sqrt{x}-1}{1}=\dfrac{2\sqrt{x}+1}{\sqrt{x}+1}\)