Question

Answer 1

\(\dfrac{2x+5}{6}=\dfrac{2x-7}{4}\\ \Leftrightarrow4\left(2x+5\right)=6\left(2x-7\right)\\ \Leftrightarrow8x+20=12x-42\\ \Leftrightarrow12x-42-8x-20=0\\ \Leftrightarrow4x-62=0\\ \Leftrightarrow x=\dfrac{31}{2}\)

Answer 2

\(\dfrac{2x+5}{6}=\dfrac{2x}{4}-7\)

=>2(2x+5)=12x-84

=>12x-84=4x+10

=>8x=94

hay x=47/4