Question

Answer 1

ĐKXĐ:...

\(\sqrt{4x^2-9}=2\sqrt{2x-3}\\ \Leftrightarrow4x^2-9=4\left(2x-3\right)\\ \Leftrightarrow4x^2-9=8x-12\\ \Leftrightarrow4x^2-8x+3=0\\ \Leftrightarrow\left(4x^2-2x\right)-\left(6x-3\right)=0\\ \Leftrightarrow2x\left(2x-1\right)-3\left(2x-1\right)=0\\ \Leftrightarrow\left(2x-3\right)\left(2x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\left(tm\right)\\x=\dfrac{1}{2}\left(ktm\right)\end{matrix}\right.\)