số sản phẩm đội 1 làm đc là: 

\(1500\cdot\dfrac{2}{5}=600\left(\text{sản phẩm}\right)\)

số sản phẩm đội 2 làm đc là: 

\(600\cdot\dfrac{3}{4}=450\left(\text{sản phẩm}\right)\)

số sản phẩm đội 3 làm đc là:

1500 - 600 - 450 = 450 (sản phẩm)

\(58.\left(3\dfrac{1}{29}-2\dfrac{1}{58}\right)\)
\(=58.\left(\dfrac{88}{29}-\dfrac{117}{58}\right)\)
\(=58.\dfrac{88}{29}-58.\dfrac{117}{58}\)
\(=176-117\)
\(=59\)

\(58\left(3\dfrac{1}{29}-2\dfrac{1}{58}\right)\)

\(=58\left(3+\dfrac{1}{29}-2-\dfrac{1}{58}\right)\)

\(=58\left(1+\dfrac{1}{29}-\dfrac{1}{58}\right)=58\left(1+\dfrac{1}{58}\right)\)

\(=58+1=59\)

\(\dfrac{15}{37}\left(\dfrac{38}{41}-\dfrac{74}{35}\right)-\dfrac{38}{41}\left(\dfrac{15}{37}+\dfrac{82}{76}\right)\)

\(=\dfrac{15}{37}\cdot\dfrac{38}{41}-\dfrac{15}{37}\cdot\dfrac{74}{35}-\dfrac{38}{41}\cdot\dfrac{15}{37}-\dfrac{34}{41}\cdot\dfrac{41}{38}\)

\(=-\dfrac{15}{37}\cdot\dfrac{74}{35}-\dfrac{34}{41}\cdot\dfrac{41}{38}\)

\(=-\dfrac{3}{7}\cdot2-\dfrac{17}{19}=\dfrac{-6}{7}-\dfrac{17}{19}=\dfrac{-233}{133}\)

\(\dfrac{4}{7}+\dfrac{15}{4}-\dfrac{11}{4}+\dfrac{3}{7}-\dfrac{1}{2}+\dfrac{1}{3}\)

\(=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{15}{4}-\dfrac{11}{4}\right)+\left(-\dfrac{1}{2}+\dfrac{1}{3}\right)\)

\(=\dfrac{7}{7}+\dfrac{4}{4}-\dfrac{1}{6}=2-\dfrac{1}{6}=\dfrac{11}{6}\)

\(\dfrac{4}{7}+\dfrac{15}{4}-\dfrac{11}{4}+\dfrac{3}{7}-\dfrac{1}{2}+\dfrac{1}{3}\)
\(=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{15}{4}-\dfrac{11}{4}\right)-\left(\dfrac{1}{2}-\dfrac{1}{3}\right)\)
\(=\dfrac{8}{8}+\dfrac{4}{4}-\left(\dfrac{3}{6}-\dfrac{2}{6}\right)\)
\(=1+1-\dfrac{1}{6}\)
\(=\dfrac{11}{6}\)

\(\dfrac{5}{7}-\dfrac{4}{19}+\dfrac{2}{7}-\dfrac{15}{19}-\dfrac{1999}{2006}\)
\(=\left(\dfrac{5}{7}+\dfrac{2}{7}\right)-\left(\dfrac{4}{19}+\dfrac{15}{19}\right)-\dfrac{1999}{2006}\)
\(=\dfrac{7}{7}-\dfrac{19}{19}-\dfrac{1999}{2006}\)
\(=1-1-\dfrac{1999}{2006}\)
\(=\dfrac{-1999}{2006}\)

\(A=\dfrac{30\cdot4^7\cdot3^{29}-5\cdot14^5\cdot2^{12}}{54\cdot6^{14}\cdot9^7-12\cdot8^5\cdot7^5}-0,2\left(3\right)\)

\(=\dfrac{2\cdot3\cdot5\cdot2^{14}\cdot3^{29}-5\cdot2^5\cdot7^5\cdot2^{12}}{2\cdot3^3\cdot2^{14}\cdot3^{14}\cdot3^{14}-2^2\cdot3\cdot2^{15}\cdot7^5}-0,2\left(3\right)\)

\(=\dfrac{2^{15}\cdot3^{30}\cdot5-2^{17}\cdot7^5\cdot5}{2^{15}\cdot3^{31}-2^{17}\cdot3\cdot7^5}-0,2\left(3\right)\)

\(=\dfrac{5\cdot2^{15}\left(3^{30}-7^5\right)}{2^{15}\cdot3\left(3^{30}-7^5\right)}-0,2\left(3\right)=\dfrac{5}{3}-\dfrac{7}{30}\)

\(=\dfrac{50}{30}-\dfrac{7}{30}=\dfrac{43}{30}\)

\(17\left(\dfrac{5}{17}-\dfrac{1}{34}+\dfrac{1}{2}\right)\)

\(=17\left(\dfrac{10}{34}-\dfrac{1}{34}+\dfrac{17}{34}\right)\)

\(=17\left(\dfrac{9}{34}+\dfrac{17}{34}\right)\)

\(=17\cdot\dfrac{26}{34}=17\cdot\dfrac{13}{17}\)

=13

\(\dfrac{7}{10}-\left(\dfrac{7}{6}:\dfrac{7}{3}+\dfrac{1}{5}\right)\)

\(=\dfrac{7}{10}-\left(\dfrac{1}{2}+\dfrac{1}{5}\right)\)

\(=\dfrac{7}{10}-\dfrac{7}{10}=0\)

\(\left(\dfrac{11}{7}-\dfrac{3}{5}\right)-\left(\dfrac{4}{9}+\dfrac{4}{7}\right)+\left(\dfrac{8}{5}-\dfrac{5}{9}\right)\)

\(=\dfrac{11}{7}-\dfrac{3}{5}-\dfrac{4}{9}-\dfrac{4}{7}+\dfrac{8}{5}-\dfrac{5}{9}\)

\(=\left(\dfrac{11}{7}-\dfrac{4}{7}\right)+\left(-\dfrac{3}{5}+\dfrac{8}{5}\right)+\left(-\dfrac{4}{9}-\dfrac{5}{9}\right)\)

\(=\dfrac{7}{7}+\dfrac{5}{5}-\dfrac{9}{9}\)

=1+1-1

=1