=>(x-3)(x-2)=0
=>x=2 hoặc x=3
x(x-3)-(2x-6)=0
x(x-3)-2(x-3)=0
(x-3)(x-2)=0
\(\Leftrightarrow\)x-3=0 hoặc x-2=0
⇔x=3 hoặc x=2
Vậy x∈\(\left\{3;2\right\}\)
A) 2x³+6x²=x²+3x
B) (2x+5)²=(x+2)²
C) x²-5x+6=0
D) (2x-7)²-6(2x-7)(x-3)=0
E) (x-2)(x+1)=x²-4
G) 2x(2x-3)=(3-2x)(2-5x)
H) (1-x)(5x+3)=(3x-7)(x-1)
F) (x+6)(3x-1)+x+6=0
I) (4x-1)(x-3)=(x-3)(5x+2)
K) (x+4)(5x+9)-x-4=0
H) (x+3)(x-5)+(x+3)(3x-4)=0
M) (2x+3)(-x+7)=0
a. 2x – 3 = 4x + 6 b. x 2 1 x x 3 4 8 = 0 c. x(x – 1) + x(x + 3) = 0 d. x x 2x 2x 6 2x 2 (x 1)(x 3)
a. 2x – 3 = 4x + 6 b. x+2/4-x+3-1-x/8=0 c. x(x – 1) + x(x + 3) = 0 d. x/2x-6-x/2x+2=2x/(x+1)(x-3)
A) 2x³+6x²=x²+3x
B) (2x+5)²=(x+2)²
C) x²-5x+6=0
D) (2x-7)²-6(2x-7)(x-3)=0
E) (x-2)(x+1)=x²-4
G) 2x(2x-3)=(3-2x)(2-5x)
H) (1-x)(5x+3)=(3x-7)(x-1)
F) (x+6)(3x-1)+x+6=0
I) (4x-1)(x-3)=(x-3)(5x+2)
K) (x+4)(5x+9)-x-4=0
H) (x+3)(x-5)+(x+3)(3x-4)=0
Help me
A) 2x³+6x²=x²+3x
B) (2x+5)²=(x+2)²
C) x²-5x+6=0
D) (2x-7)²-6(2x-7)(x-3)=0
E) (x-2)(x+1)=x²-4
G) 2x(2x-3)=(3-2x)(2-5x)
H) (1-x)(5x+3)=(3x-7)(x-1)
F) (x+6)(3x-1)+x+6=0
I) (4x-1)(x-3)=(x-3)(5x+2)
K) (x+4)(5x+9)-x-4=0
H) (x+3)(x-5)+(x+3)(3x-4)=0
A) 2x³+6x²=x²+3x
B) (2x+5)²=(x+2)²
C) x²-5x+6=0
D) (2x-7)²-6(2x-7)(x-3)=0
E) (x-2)(x+1)=x²-4
G) 2x(2x-3)=(3-2x)(2-5x)
H) (1-x)(5x+3)=(3x-7)(x-1)
F) (x+6)(3x-1)+x+6=0
I) (4x-1)(x-3)=(x-3)(5x+2)
K) (x+4)(5x+9)-x-4=0
H) (x+3)(x-5)+(x+3)(3x-4)=0
bài 7 tìm x
1,x(x+3)-5(x+3)=0 2,5x(x-1)=x-1
3,(x+1)=(x+1)\(^2\) 4,x(2x-3)-2(3-2x)=0
5,\(\left(x-2\right)^2-4=0\) 6,\(36x^2=49\)
7,\(2x\left(x-6\right)-x+6=0\) 8,\(3x\left(2x-1\right)-24x+12=0\)
9,\(x^2-6x+8=0\) 10,\(x^2+2x-15=0\)
1.x^3+4x^2+x-6=0
2.x^3-6x^2+11x-6=0
3.x^3-4x^2+x+6=0
4.x^3-3x^2+4=0
5.x-ab/a+b + x-bc/b+c + x-ca/c+a=a+b+c(voi a,b,c,>0)
6.x^2+2x+1/x^2+2x+2 + x^2+2x+2/x^2+2x+3=7/6
Giải các phương trình sau. 2x-1=2-x ; x-5x-1/6=8-3x/4. ; x/3 - 2x+1/2=x/6 - x ; (2x-5)(x+3)=0. ; (1-7)(2+x)=0
