\(x\left(x-2\right)-\left(7x-14\right)=0\\ \Leftrightarrow x\left(x-2\right)-7\left(x-2\right)=0\\ \Leftrightarrow\left(x-2\right)\left(x-7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=7\end{matrix}\right.\)
x ( x - 2 ) - ( 7x - 14 ) = 0
x ( x - 2 ) - 7 ( x - 2 ) = 0
( x - 2 ) ( x - 7 ) = 0
TH1: x - 2 = 0 TH2: x - 7 = 0
=> x = 2 => x = 7
Vậy x = 2 hoặc x = 7
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