Question

2x^2+7x-9=0

tìm x trình bày ra luôn

 

Answer 1

\(2x^2+7x-9=0\Leftrightarrow\left(x-1\right)\left(x+\dfrac{9}{2}\right)=0\)

\(x\in\left\{1;\dfrac{-9}{2}\right\}\)

Answer 2

<=> 2x² -2x +9x -9 =0

<=> 2x(x-1) + 9 (x-1) = 0

<=> (2x+9)(x-1) = 0

<=> 2x + 9 =0 hoặc x-1 = 0

<=> x= -9/2 hoặc x= 1