Question

x^3+x^2+1/3x+1/27

Giúp mik với,mik đag gấp

Answer 1

\(x^3+x^2+\dfrac{1}{3}x+\dfrac{1}{27}\)

\(=x^3+3\cdot\dfrac{1}{3}\cdot x^2+3\cdot\left(\dfrac{1}{3}\right)^2\cdot x+\left(\dfrac{1}{3}\right)^3\)

\(=\left(x+\dfrac{1}{3}\right)^3\)

Answer 2

=x^3+3*x^2*1/3+3*x*(1/3)^2+(1/3)^3

=(x+1/3)^3