ĐKXĐ: x<>3
\(\Leftrightarrow\dfrac{\left(x+2\right)\left(x-3\right)}{x-3}=0\)
=>x+2=0
hay x=-2(nhận)
đk : x khác 3
\(\dfrac{x^2+2x-3x-6}{x-3}=0\Leftrightarrow\dfrac{x\left(x-3\right)+2\left(x-3\right)}{x-3}=0\Leftrightarrow x+2=0\Leftrightarrow x=-2\left(tm\right)\)