\(=\dfrac{1+5-x}{x+1}=\dfrac{6-x}{x+1}\)
\(\dfrac{x+1}{x^2+2x+1}+\dfrac{5-x}{x+1}=\dfrac{x+1}{\left(x+1\right)^2}+\dfrac{5-x}{x+1}=\dfrac{1}{x+1}+\dfrac{5-x}{x+1}=\dfrac{6-x}{x+1}\)
a) 2(7x+10)+5=3(2x-3)-9x
b) (x+1)(2x-30=(2x-10)(x+5)
c) 2x+x(x+1)(x-1)=(x+1)(x2-x+1)
d) (x-1)3-x(x+1)2=5x(2-x)-11(x+2)
Rút gọn các biểu thức :
a)5(x-2)+2(x+3)
b)(x+1)^2-(x-5)(x+2)
c)(x+7)(x-7)-(x-1)(x+1)
d)(x+5)^2+x(2x+5)^2.(2x+5)(2x-1)
a)x-3/x-2 + x-2/x-4 = -1
b)3x + 12 = 0
c)5 + 2x = x - 5
d)2x(x - 2) + 5(x - 2) = 0
e)3x-4/2 = 4x+1/3
f)2x/x-1 - x/x+1 =1
g)2x/x-1 + 3-2x/x+2 = 6/(x-1)(x+2)
1.giải phương trình :
1)1 + 2/x-1 + 1/x+3=x^2+2x-7/x^2+2x-3
2)x/x^2+5x+6=2/x^2+3x+2 (x=3)
3)1/x^2+9x+20 - 1/x^2+8x+12=x^2-2x-33/x^2+8x+15 (x=-5,7)
4)x+5/3x-6 - 1/2=2x-3/2x-4 (x=25/7)
5)x-1/x^3+1 + 2x+3/x^2-x+1=2x+4/x+1 - 2(x=0)
Phân tích các đa thức sau thành nhân tử
a, (x-3)(x-1)-3(x-3)
b, (x-1)(2x+1)+3(x-1)(x+2)(2x+1)
c, (6x+3)-(2x-5)(2x+1)
d, (x-5)^2+(x+5)(x-5)-(5-x)(2x+1)
e, (3x-2)(4x-3)-(2-3x)(x-1)-2(3x-2)(x+1)
Bài 2*: Phân tích đa thức thành nhân tử:
a) 3x2-3y2-2(x-y)2
b) x2-y2-2x-2y
c) (x-1)(2x+1)+3(x-1)(x+2)(2x+1)
d) (x-5)2+(x+5)(x-5)-(5-x)(2x+1)
Rút gọn:
1 , -3x(x+2)2+(x+3)(x-1)(x+1)-(2x-3)2
2 , (x-3)(x+3)(x+2)-(x-1)(x2-3)-5x(x+4)2-(x-5)2
3 , 2x(x-4)2-(x+5)(x-2)(x+2)+2(x+5)2-(x-1)2
4 , (x+5)2-4x(2x+3)2-(2x-1)(x+3)(x-3)
5 , -2x(3x+2)(3x-2)+5(x+2)2-(x-1)(2x-1)(2x+1)
Giúp mình với ạ:>
Nhóm nhiều hạng tử
a) (x - 1)(2x + 1) + 3(x - 1)( x + 2 )
b) (6x + 3) - (2x - 5)(2x + 1)
c) (x - 5)2 + (x + 5)(x - 5) - (5 - x)(2x + 1)
e) (3x - 2)(4x - 3) - (2 - 3x)( x - 1) - 2(3x - 2)(x + 1)
giải phương trình sau
1/ ( x-5)^2 +3(x-5) =0
2/ ( x^2-9) +2 (x-3) =0
3/ ( 2x+1)^2+(x-1)(2x+1)=0
4/ (x-1) (x+3) +( x+3)^2=0
5/ ( x+5)^2 -16x^2 =0
6/ x^3-2x^2-x+2=0
b) 5+2x=x-5. c) 2x(x+2) +5(x-2)=0
h)2/x+1-1/x-2=3x-11/(x+1)(x-2). i) 3x-12 =0
f) x-3/5 + 1+2x/3=6.
