\(\left(x+1\right)^2=16\\ \Rightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
\(\left(x+1\right)^2=16\\ \Rightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
\(\left(x+1\right)^2=4^2\) hoặc \(\left(x+1\right)^2=\left(-4^2\right)\)
\(=>x+1=4\) \(=>x+1=\left(-4\right)\)
\(x=4-1\) \(x=-4-1\)
\(x=3\) \(x=-5\)
Vậy \(x=3\) hoặc \(x=-5\)