Question

x-\(\dfrac{2x-5}{5}+\dfrac{x+8}{6}=7+\dfrac{x-1}{3}\)

Answer 1

\(x-\dfrac{2x-5}{5}+\dfrac{x+8}{6}=7+\dfrac{x-1}{3}\)

\(\Leftrightarrow30x-12x+30+5x+40=210+10x-10\)

\(\Leftrightarrow23x+70=200+10x\Leftrightarrow13x=130\Leftrightarrow x=10\)

Answer 2

Ta có: \(x-\dfrac{2x-5}{5}+\dfrac{x+8}{6}=7+\dfrac{x-1}{3}\)

\(\Leftrightarrow\dfrac{30x}{30}-\dfrac{6\left(2x-5\right)}{30}+\dfrac{5\left(x+8\right)}{30}=\dfrac{210+10\left(x-1\right)}{30}\)

Suy ra: \(30x-12x+30+5x+40=210+10x-10\)

\(\Leftrightarrow23x+70-10x-200=0\)

\(\Leftrightarrow13x=130\)

hay x=10