-x - 2/3 = -6/7
-x = -6/7 + 2/3
-x = -4/21
x = 4/21
\(-x-\dfrac{2}{3}=\dfrac{-6}{7}\)
\(\Rightarrow-x=\dfrac{-6}{7}+\dfrac{2}{3}\)
\(\Rightarrow-x=\dfrac{-18}{21}+\dfrac{14}{21}\)
\(\Rightarrow-x=\dfrac{-4}{21}\)
\(\Rightarrow x=\dfrac{4}{21}\)
Vậy: \(x=\dfrac{4}{21}\)
#\(Toru\)
