`(x-3)^2-(x-1)(x+1)=10`
`<=>x^2-6x+9-x^2+1=10`
`<=>-6x=0`
`<=>x=0`
=>x^2-6x+9-x^2+1=10
=>-6x+10=10
=>x=0
Tính (rút gọn )
(x-10)^2-2(x-10)(5x-3)+(5x+3)
(x-2)^3-x(x-3)^2
(x-2)(x^2+2x+4)-x(x+1)(x-1)
(x+3)(x^2-3x+9)-x(x^2-1)
a) 2(7x+10)+5=3(2x-3)-9x
b) (x+1)(2x-30=(2x-10)(x+5)
c) 2x+x(x+1)(x-1)=(x+1)(x2-x+1)
d) (x-1)3-x(x+1)2=5x(2-x)-11(x+2)
1.giải các phương trình sau:
a, 3(2x+1)/4 - 5x+3/6 = 2x-1/3 - 3-x/4
b, 19/4 - 2(3x-5)/5 = 3-2x/10 - 3x-1/4
c, x-2*3/2+3 + x-3*5/3+5 + x-5*2/5+2 = 10
d, x-3/5*7 + x-5/3*7 + x-7/3*5 = 2(1/3 + 1/5 + 1/7)
2. giải các phương trình:
a, x-1/9 + x-2/8 = x-3/7 + x-4/6
b, (1/1*2 + 1/2*3 + 1/3*4 + ... + 1/9*10) (x-1) + 1/10x = x- 9/10
x^2/3+48/x^2-10(x/3-4/x)=0
10(x-2/x+1)^2+(x+2/x-1)^2-11(x^2-4/x-1)=0
giải phương trình:
a/x-1/x^2-x+1 - x+/x^2+x+1 = 10/x(x^4+x^2+1)
b/ x+9/10 + x+10/9 = 9/x+10 + 10/x+9
c/ x^2-2x+2/x-1 + x^2-8x+20 = x^2-4x+6/x-2 + x^2-6x +12/x-3
. Tìm x biết rằng:
a)(x + 1)3 – (x + 2)(x – 1)2 – 3(x – 3)(x + 3) = 5
b)(x + 1)3 + (x – 1)3 = (x + 2)3 + (x – 2)3
c) (x + 1)3 - (x - 1)3 - 6(x - 1)2 = -10
Rút gọn
A=x(5x-3)-x^2(x-1)+x(x^2-62)-10+3x B=x(x^2+x+1)-x^2(x+1)-x+5
C=-3xy(-x+5y)+5y^2(3x-2y)+2(5y^2-3/2x^2y-2)
D=(3-x-6y)(x^2+2xy+4y^2)-3(x^3-8y^3+10)
a) (x+3)^3-x(3x+1)^2+(2x+1)(4x^2-2x+1)=28
b) (x-1)^3 - 4x(x+1)(x-1)+3(x-1)(x^2+x+1)=3x^2+10
Tính (rút gọn )
(x-10)^2-2(x-10)(5x-3)+(5x-3)^2
(x-2)^3-x(x-3)^2
(x-2)(x^2+2x+4)-x(x+1)(x-1)
(x+3)(x^2-3x+9)-x(x^2-1)
\(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)
\(\frac{x+2}{x+1}-\frac{1}{x-2}=1-\frac{3}{x^2-x-2}\)
\(\frac{1}{x}+2=\left(\frac{1}{x}+2\right)\left(x^2+1\right)\)
\(\left(x+1+\frac{1}{x}\right)^2=\left(x-1-\frac{1}{x}\right)^2\)
\(\frac{x+9}{10}+\frac{x+10}{9}=\frac{9}{x+10}+\frac{10}{x+9}\)
