Lời giải:
$(x-10)^2-2(x-10)(5x-3)+(5x-3)^2$
$=[(x-10)-(5x-3)]^2=(-4x-7)^2=(4x+7)^2$
$(x-2)^3-x(x-3)^2=x^3-6x^2+12x-8-x(x^2-6x+9)$
$=x^3-6x^2+12x-8-x^3+6x^2-9x$
$=3x-8$
$(x-2)(x^2+2x+4)-x(x+1)(x-1)$
$=(x^3-2^3)-x(x^2-1)$
$=x^3-8-x^3+x=x-8$
$(x+3)(x^2-3x+9)-x(x^2-1)=(x^3+3^3)-x^3+x$
$=x+27$