\(x=\dfrac{3+x}{5}+\dfrac{11}{5}\)
\(x=\dfrac{14+x}{5}\)
\(5x=x+14\)
\(4x=14\)
\(x=\dfrac{7}{2}\)
\(x-\dfrac{11}{5}=\dfrac{3+x}{5}\)
\(x=\dfrac{3+x}{5}+\dfrac{11}{5}\)
\(x=\dfrac{3+x+11}{5}\)
\(x=\dfrac{14+x}{5}\)
\(5x=14+x\)
\(4x=14\)
\(x=\dfrac{14}{4}\)
\(=>\dfrac{5x-11}{5}=\dfrac{3+x}{5}\)
\(=>25x-55=15+5x\)
\(=>25x-55-15-5x=0\)
\(\left(25x-5x\right)+\left(-55-15\right)=0\)
\(20x-70=0\)
\(20x=70\)
\(x=\dfrac{7}{2}\)
\(x-\dfrac{11}{5}=\dfrac{3+x}{5}\)
\(\dfrac{5x}{5}-\dfrac{11}{5}=\dfrac{3+x}{5}\)
\(\dfrac{5x-11}{5}=\dfrac{3+x}{5}\)
=> \(5x-11=3+x\)
\(5x-x=11+3\)
4x = 14
\(x=\dfrac{7}{2}\)
\(x=\dfrac{7}{2}\)
Em nghĩ thế thôi :> (em học trước)
