<=>x-1=0 hoặc 2x-1=0 hoặc 9-x=0
<=>x=1 hoặc 2x=1 hoặc-x=-9
<=>x=1 hoặc x=1/2 hoặc x=9
Vậy x=1 hoặc x=1/2 hoặc x=9
1: 3/x+1 + 2/x+2 = 5x+4/x2+ 3x + 2
2: 2/3x + 1 - 15/6x2-x-1 = 3/2x - 1
3: 9/3x - 1 - 5-x/3x2-4x+1 = 4/x+ 1
4:5/x - 2 + 2/x+4 = 3x/x2 + 2x - 8
5: 4/x+6 + 1/x - 3 = 9/x2 + 3x - 18
6:x/x-3 - 2x2 +9/2x2 - 3x - 9= 1/2x + 3
giải các phương trinh sau :
a) 3(2x - 1 ) - 2 (1 - x ) = x + 9
b) -3 ( 2x - 1 ) - 2 (1 - x ) = x + 9 ( 1 - x )
c) ( 1 - x ) ( 2x - 1 ) - 2 (2 - x ) ( 2 + x ) = x = 9
giải các phương trinh sau :
a) 3(2x - 1 ) - 2 (1 - x ) = x + 9
b) -3 ( 2x - 1 ) - 2 (1 - x ) = x + 9 ( 1 - x )
c) ( 1 - x ) ( 2x - 1 ) - 2 (2 - x ) ( 2 + x ) = x = 9
Giải phương trình
a) 2x-1/x+1 = -2x+1/x-5
b) 1/x-3 + 2/x^2-9 = x/x^2-2x-3
Giải phương trình
1) 7 - (2x + 4) = - (x +4)
2) ( x - 1) - (2x -1) = 9 - x
3) (x + 1) - (2x - 3) = ( 2x - 1)( x + 5)
a, (x-1)*x+x^2-7=8
b, (2x+1)*x-(2x-1)=9
c, (x-1)*(x+1)-(x^2+9)=12
d, (3x+1)*(x+1)-x(3x+1)
e, (2x-1)*x^2*(x^3-x^2+x-1)=10
tìm x biết
Bài 2: Tìm x biết:
1,x\(^2\)+4x+4=25
2,(5-2x)\(^2\)-16=0
3,(x-3)\(^3\)-(x-3)(x\(^2\)+3x+9)+9(x+1)\(^2\)=15
4,3(x+2)\(^2\)+(2x-1)\(^2\)-7(x-3)9x+3)=36
5,(x-3)(x\(^2\)+3x+9)+x(x+2)(2-x)=1
6,(2x+1)\(^2\)-4(x+2)\(^2\)=9
7,(x+3)\(^{^{ }2}\)-(x-4)(x+8)=1
Tìm x :
a) x (3x + 1) + (x -1)2 - (2x + 1)(2x -1) = 0
b) (x + 1)3 + (2 - x)3 - 9(x - 3)(x+3) = 0
c) (x - 1)3 - (x + 3)(x2 - 3x + 9) + 3x2 = 25
d) (x + 2)3 - ( x +1)(x2 - x + 1) - 6(x - 1)2 = 23
e) (x + 3)(x2 - 3x + 9) - x(x - 2)(x+2) + 11 = 0
f) x(x - 3) - x + 3 = 0
a)4/x+2+2/x-2+5x-6/4-x2 ; b)1-3x/2x+3x-2/2x-1+3x-2/2x-4x2 ; c)1/x2+6x+9+1/6x-x2-9+x/x2-9
Các bạn giúp mình với !!!
a,(3x-1)2+(x+3)2-10(x+1)(x-1)=0
b,(x+3)3+(2x+1)(4x2-2x+1)-9x2(x+1)=54
c,(x-3)3-(x-3)(x2+3x+9)+9(x+1)2=-33
