Question

Giải phương trình

1) 7 - (2x + 4) = - (x +4)

2) ( x - 1) - (2x -1) = 9 - x

3) (x + 1) - (2x - 3) = ( 2x - 1)( x + 5)

Answer 1

\(1,\Leftrightarrow7-2x-4=-x-4\)

\(\Leftrightarrow x-2x=-4-7+4\)

\(\Leftrightarrow-x=-7\)

\(\Leftrightarrow x=7\)

Vậy \(S=\left\{7\right\}\)

\(2,\Leftrightarrow x-1-2x+1=9-x\)

\(\Leftrightarrow x+x-2x=9-1+1\)

\(\Leftrightarrow0x=9\)

\(\Rightarrow x\in\varnothing\)

Vậy \(S=\left\{\varnothing\right\}\)

\(3,\Leftrightarrow2x^2+3x-2x+3=2x^2+10x-x-5\)

\(\Leftrightarrow2x^2-2x^2+3x-2x-10x+x=-5-3\)

\(-8x=-8\)

\(\Rightarrow x=1\)

Vậy \(S=\left\{1\right\}\)