Điều kiện phải là \(0\le x< 1\)
\(\sqrt{\frac{1-x\sqrt{x}}{\left(1+x+\sqrt{x}\right)\left(1-x\right)}}:\frac{1}{\sqrt{1+\sqrt{x}}}=\sqrt{\frac{\left(1-\sqrt{x}\right)\left(x+\sqrt{x}+1\right)}{\left(x+\sqrt{x}+1\right)\left(1-\sqrt{x}\right)\left(1+\sqrt{x}\right)}}.\sqrt{1+\sqrt{x}}\)
\(=\sqrt{\frac{1}{\sqrt{x}+1}}.\sqrt{1+\sqrt{x}}=1\)