\(\sqrt{13+4\sqrt{3}}\cdot\sqrt{28+6\sqrt{3}}-5\sqrt{3}\)
\(=\sqrt{\left(2\sqrt{3}+1\right)^2}\cdot\sqrt{\left(3\sqrt{3}+1\right)^2}-5\sqrt{3}\)
\(=\left(2\sqrt{3}+1\right)\left(3\sqrt{3}+1\right)-5\sqrt{3}\)
\(=6\cdot3+2\sqrt{3}+3\sqrt{3}+1-5\sqrt{3}\)
\(=18+1=19\)