Question

Với a \(a\le0,tính\sqrt{\dfrac{-2a}{3}}.\sqrt{\dfrac{-3a}{8}}\)

Answer 1

\(\sqrt{\dfrac{-2a}{3}}.\sqrt{\dfrac{-3a}{8}}=\sqrt{\dfrac{-2a}{3}.\dfrac{-3a}{8}}=\sqrt{\dfrac{a^2}{4}}=\dfrac{\left|a\right|}{2}=-\dfrac{a}{2}\left(do.a\le0\right)\)