MIK SỬA LẠI ĐỀ CÂU B
a) \(27^5:81^3=\left(3^3\right)^5:\left(3^4\right)^3=3^{15}:3^{12}=3^3\)
b) \(3^9:81^3=3^9:\left(3^4\right)^3=3^9:3^{12}=3^{-3}\)
a) \(\left(3^3\right)^5:\left(3^4\right)^3\)
= \(3^{15}:3^{12}\)
= \(3^3\)
a) \(27^5:81^3=3^{15}:3^{12}=3^3\)
b) \(3^9:81^3=3^9:3^{12}=\dfrac{1}{3^3}=\left(\dfrac{1}{3}\right)^3\)