a) \(9x^2+6x+1=\left(3x+1\right)^2\)
b)\(x^2-x+\frac{1}{4}=\left(x-\frac{1}{2}\right)^2\)
c)\(x^2y^4-2xy^2+1=\left(xy^2-1\right)^2\)
d) \(x^2+\frac{2}{3}x+\frac{1}{9}=\left(x+\frac{1}{3}\right)^2\)
a) 9x2 + 6x + 1 = ( 3x + 1 )2
b) x2 - x + 1/4 = ( x - 1/2)2
c) x2 . y4 - 2xy2 + 1 = ( xy2 - 1 ) 2
d) x2 + 2/3x + 1/9 = (x+1/3)2
a) \(9x^2+6x+1\)
\(=\left(3x\right)^2+6x+1\)
\(=\left(3x+1\right)^2\)
b) \(x^2-x+\frac{1}{4}\)
\(=x^2-2x\frac{1}{2}+\frac{1}{2}-\frac{1}{2}+\frac{1}{4}\)
\(=\left(x-\frac{1}{2}\right)^2\)
c) \(x^2y^4-2xy^2+1\)
.... Rút gọn lũy thừa cao
d ) Tương tự câu b . Làm theo cách thêm bớt