Ta có: \(n_{CaCl_2}=\dfrac{2,22}{111}=0,02\left(mol\right)\)
PT: \(CaCl_2+2AgNO_3\rightarrow Ca\left(NO_3\right)_2+2AgCl_{\downarrow}\)
_____0,02_______________0,02__________0,04 (mol)
a, \(m_{AgCl}=0,04.143,5=5,74\left(g\right)\)
b, \(C_{M_{Ca\left(NO_3\right)_2}}=\dfrac{0,02}{0,03+0,07}=0,2\left(M\right)\)
\(n_{CaCl2}=\dfrac{2,22}{111}=0,02\left(mol\right)\)
Pt : \(CaCl_2+AgNO_3\rightarrow Ca\left(NO_3\right)_2+2AgCl|\)
0,02 0,02 0,04
a) \(m_{AgCl}=0,04.143,5=5,74\left(g\right)\)
b) \(C_{M_{Ca\left(NO3\right)2}}=\dfrac{0,02}{0,03+0,07}=0,2\left(M\right)\)
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