Question

(trình bày) Giải phương trình:

 

𝑥²−3𝑥=−2

 

 

Answer 1

\(x^2-3x+2=0\)

\(\left(x^2-x\right)-\left(2x-2\right)=0\)

\(\left(x-1\right)\left(x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)

Answer 2

x=1

x=2

Answer 3

<=>x^2-3x+2=0

<=>(x-2)(x-1)=0

<=>x=2

x=1

Answer 4

x²-3x=-2

=>x²-3x+2=0

=>x²-1x-2x+2=0

=>(x²-1x)-(2x-2)=0

=>x(x-1)-2(x-1)=0

=>(x-2)(x-1)=0

=>x=2 hoặc x=1