Đáp án D
Xét
1 + x 2016 = C 2016 0 + C 2016 1 x + C 2016 2 x 2 + C 2016 3 x 3 + ... + C 2016 2016 x 2016
chọn x=1 ta có
1 + 1 2016 = C 2016 0 + C 2016 1 + C 2016 2 + C 2016 3 + ... + C 2016 2016 ⇔ 2 2016 − C 2016 0 = C 2016 1 + C 2016 2 + C 2016 3 + ... + C 2016 2016 ⇔ C 2016 1 + C 2016 2 + C 2016 3 + ... + C 2016 2016 = 2 2016 − 1