Question

Tính

\(\sqrt{2+\sqrt{3}}+\sqrt{2-\sqrt{3}}\)

Answer 1

Đặt \(A=\sqrt{2+\sqrt{3}}+\sqrt{2-\sqrt{3}}\)

      \(A^2=2+\sqrt{3}+2-\sqrt{3}+2\sqrt{\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)}\)

    \(A^2=4+2\sqrt{4-3}=4+2=6\)

=> A = can 6