a) \(3\left(2x-3\right)+5\left(x+2\right)=6x-9+5x+10=11x+1\)
b) \(3x\left(2x-8\right)+\left(6x+2\right)\left(5-x\right)=6x^2-24x+30x-6x^2+10-2x=4x+10\)
c) \(\left(x-3\right)\left(x+3\right)-\left(x-5\right)^2=x^2-9-x^2+10x-25=10x-34\)
d) \(\left(x-y\right)^3-\left(x-y\right)\left(x^2+xy+y^2\right)=x^3-3x^2y+3xy^2-y^3-x^3+y^3=3xy^2-3x^2y\)
a: Ta có: \(3\left(2x-3\right)+5\left(x+2\right)\)
\(=6x-9+5x+10\)
\(=11x+1\)
b: Ta có: \(3x\left(2x-8\right)-\left(6x-2\right)\left(x-5\right)\)
\(=6x^2-24x-6x^2+30x+2x-10\)
\(=8x-10\)
c: Ta có: \(\left(x-3\right)\left(x+3\right)-\left(x-5\right)^2\)
\(=x^2-9-x^2+10x-25\)
\(=10x-34\)
d: Ta có: \(\left(x-y\right)^3-\left(x-y\right)\left(x^2+xy+y^2\right)\)
\(=x^3-3x^2y+3xy^2-y^3-x^3+y^3\)
\(=-3x^2y+3xy^2\)
