\(2+\dfrac{1}{1+\dfrac{1}{2}}\)
\(=2+\dfrac{1}{\dfrac{3}{2}}=\dfrac{8}{3}\)
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\(2+\dfrac{1}{1+\dfrac{1}{2}}\\ =2+\dfrac{1}{\dfrac{2}{2}+\dfrac{1}{2}}\\ =2+\dfrac{1}{\dfrac{3}{2}}\\ =2+1\times\dfrac{2}{3}\\ =2+\dfrac{2}{3}\\ =\dfrac{6}{3}+\dfrac{2}{3}\\ =\dfrac{8}{3}\)
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